Optimal. Leaf size=345 \[ \frac{2 \sin (c+d x) \left (7 a^2 C-7 a b B+7 A b^2+5 b^2 C\right )}{21 b^3 d \sqrt{\sec (c+d x)}}-\frac{2 \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \left (-7 a^2 b^2 (3 A+C)+21 a^3 b B-21 a^4 C+7 a b^3 B-b^4 (7 A+5 C)\right )}{21 b^5 d}+\frac{2 \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)} E\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \left (5 a^2 b B-5 a^3 C-a b^2 (5 A+3 C)+3 b^3 B\right )}{5 b^4 d}-\frac{2 a^3 \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)} \left (A b^2-a (b B-a C)\right ) \Pi \left (\frac{2 b}{a+b};\left .\frac{1}{2} (c+d x)\right |2\right )}{b^5 d (a+b)}+\frac{2 (b B-a C) \sin (c+d x)}{5 b^2 d \sec ^{\frac{3}{2}}(c+d x)}+\frac{2 C \sin (c+d x)}{7 b d \sec ^{\frac{5}{2}}(c+d x)} \]
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Rubi [A] time = 1.4781, antiderivative size = 345, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 7, integrand size = 43, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.163, Rules used = {4221, 3049, 3059, 2639, 3002, 2641, 2805} \[ \frac{2 \sin (c+d x) \left (7 a^2 C-7 a b B+7 A b^2+5 b^2 C\right )}{21 b^3 d \sqrt{\sec (c+d x)}}-\frac{2 \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \left (-7 a^2 b^2 (3 A+C)+21 a^3 b B-21 a^4 C+7 a b^3 B-b^4 (7 A+5 C)\right )}{21 b^5 d}+\frac{2 \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)} E\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \left (5 a^2 b B-5 a^3 C-a b^2 (5 A+3 C)+3 b^3 B\right )}{5 b^4 d}-\frac{2 a^3 \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)} \left (A b^2-a (b B-a C)\right ) \Pi \left (\frac{2 b}{a+b};\left .\frac{1}{2} (c+d x)\right |2\right )}{b^5 d (a+b)}+\frac{2 (b B-a C) \sin (c+d x)}{5 b^2 d \sec ^{\frac{3}{2}}(c+d x)}+\frac{2 C \sin (c+d x)}{7 b d \sec ^{\frac{5}{2}}(c+d x)} \]
Antiderivative was successfully verified.
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Rule 4221
Rule 3049
Rule 3059
Rule 2639
Rule 3002
Rule 2641
Rule 2805
Rubi steps
\begin{align*} \int \frac{A+B \cos (c+d x)+C \cos ^2(c+d x)}{(a+b \cos (c+d x)) \sec ^{\frac{5}{2}}(c+d x)} \, dx &=\left (\sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{\cos ^{\frac{5}{2}}(c+d x) \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right )}{a+b \cos (c+d x)} \, dx\\ &=\frac{2 C \sin (c+d x)}{7 b d \sec ^{\frac{5}{2}}(c+d x)}+\frac{\left (2 \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{\cos ^{\frac{3}{2}}(c+d x) \left (\frac{5 a C}{2}+\frac{1}{2} b (7 A+5 C) \cos (c+d x)+\frac{7}{2} (b B-a C) \cos ^2(c+d x)\right )}{a+b \cos (c+d x)} \, dx}{7 b}\\ &=\frac{2 C \sin (c+d x)}{7 b d \sec ^{\frac{5}{2}}(c+d x)}+\frac{2 (b B-a C) \sin (c+d x)}{5 b^2 d \sec ^{\frac{3}{2}}(c+d x)}+\frac{\left (4 \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{\sqrt{\cos (c+d x)} \left (\frac{21}{4} a (b B-a C)+\frac{1}{4} b (21 b B+4 a C) \cos (c+d x)+\frac{5}{4} \left (7 A b^2-7 a b B+7 a^2 C+5 b^2 C\right ) \cos ^2(c+d x)\right )}{a+b \cos (c+d x)} \, dx}{35 b^2}\\ &=\frac{2 C \sin (c+d x)}{7 b d \sec ^{\frac{5}{2}}(c+d x)}+\frac{2 (b B-a C) \sin (c+d x)}{5 b^2 d \sec ^{\frac{3}{2}}(c+d x)}+\frac{2 \left (7 A b^2-7 a b B+7 a^2 C+5 b^2 C\right ) \sin (c+d x)}{21 b^3 d \sqrt{\sec (c+d x)}}+\frac{\left (8 \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{\frac{5}{8} a \left (7 A b^2-7 a b B+7 a^2 C+5 b^2 C\right )+\frac{1}{8} b \left (35 A b^2+28 a b B-28 a^2 C+25 b^2 C\right ) \cos (c+d x)+\frac{21}{8} \left (5 a^2 b B+3 b^3 B-5 a^3 C-a b^2 (5 A+3 C)\right ) \cos ^2(c+d x)}{\sqrt{\cos (c+d x)} (a+b \cos (c+d x))} \, dx}{105 b^3}\\ &=\frac{2 C \sin (c+d x)}{7 b d \sec ^{\frac{5}{2}}(c+d x)}+\frac{2 (b B-a C) \sin (c+d x)}{5 b^2 d \sec ^{\frac{3}{2}}(c+d x)}+\frac{2 \left (7 A b^2-7 a b B+7 a^2 C+5 b^2 C\right ) \sin (c+d x)}{21 b^3 d \sqrt{\sec (c+d x)}}-\frac{\left (8 \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{-\frac{5}{8} a b \left (7 A b^2-7 a b B+7 a^2 C+5 b^2 C\right )+\frac{5}{8} \left (21 a^3 b B+7 a b^3 B-21 a^4 C-7 a^2 b^2 (3 A+C)-b^4 (7 A+5 C)\right ) \cos (c+d x)}{\sqrt{\cos (c+d x)} (a+b \cos (c+d x))} \, dx}{105 b^4}+\frac{\left (\left (5 a^2 b B+3 b^3 B-5 a^3 C-a b^2 (5 A+3 C)\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \sqrt{\cos (c+d x)} \, dx}{5 b^4}\\ &=\frac{2 \left (5 a^2 b B+3 b^3 B-5 a^3 C-a b^2 (5 A+3 C)\right ) \sqrt{\cos (c+d x)} E\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \sqrt{\sec (c+d x)}}{5 b^4 d}+\frac{2 C \sin (c+d x)}{7 b d \sec ^{\frac{5}{2}}(c+d x)}+\frac{2 (b B-a C) \sin (c+d x)}{5 b^2 d \sec ^{\frac{3}{2}}(c+d x)}+\frac{2 \left (7 A b^2-7 a b B+7 a^2 C+5 b^2 C\right ) \sin (c+d x)}{21 b^3 d \sqrt{\sec (c+d x)}}-\frac{\left (\left (21 a^3 b B+7 a b^3 B-21 a^4 C-7 a^2 b^2 (3 A+C)-b^4 (7 A+5 C)\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{1}{\sqrt{\cos (c+d x)}} \, dx}{21 b^5}-\frac{\left (a^3 \left (A b^2-a (b B-a C)\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{1}{\sqrt{\cos (c+d x)} (a+b \cos (c+d x))} \, dx}{b^5}\\ &=\frac{2 \left (5 a^2 b B+3 b^3 B-5 a^3 C-a b^2 (5 A+3 C)\right ) \sqrt{\cos (c+d x)} E\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \sqrt{\sec (c+d x)}}{5 b^4 d}-\frac{2 \left (21 a^3 b B+7 a b^3 B-21 a^4 C-7 a^2 b^2 (3 A+C)-b^4 (7 A+5 C)\right ) \sqrt{\cos (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \sqrt{\sec (c+d x)}}{21 b^5 d}-\frac{2 a^3 \left (A b^2-a (b B-a C)\right ) \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{a+b};\left .\frac{1}{2} (c+d x)\right |2\right ) \sqrt{\sec (c+d x)}}{b^5 (a+b) d}+\frac{2 C \sin (c+d x)}{7 b d \sec ^{\frac{5}{2}}(c+d x)}+\frac{2 (b B-a C) \sin (c+d x)}{5 b^2 d \sec ^{\frac{3}{2}}(c+d x)}+\frac{2 \left (7 A b^2-7 a b B+7 a^2 C+5 b^2 C\right ) \sin (c+d x)}{21 b^3 d \sqrt{\sec (c+d x)}}\\ \end{align*}
Mathematica [A] time = 6.59163, size = 538, normalized size = 1.56 \[ \frac{4 b^2 \sin (c+d x) \left (70 a^2 C+42 b (b B-a C) \cos (c+d x)-70 a b B+70 A b^2+15 b^2 C \cos (2 (c+d x))+65 b^2 C\right )-\frac{2 \cos (c+d x) \cot (c+d x) (a \sec (c+d x)+b) \left (4 a b^2 \sqrt{-\tan ^2(c+d x)} \sqrt{\sec (c+d x)} \left (-28 a^2 C+28 a b B+35 A b^2+25 b^2 C\right ) \Pi \left (-\frac{a}{b};\left .-\sin ^{-1}\left (\sqrt{\sec (c+d x)}\right )\right |-1\right )-2 b^2 \sqrt{-\tan ^2(c+d x)} \sqrt{\sec (c+d x)} \left (35 a^2 b B-35 a^3 C-a b^2 (35 A+13 C)+63 b^3 B\right ) \left (\Pi \left (-\frac{a}{b};\left .-\sin ^{-1}\left (\sqrt{\sec (c+d x)}\right )\right |-1\right )+F\left (\left .\sin ^{-1}\left (\sqrt{\sec (c+d x)}\right )\right |-1\right )\right )-21 \left (-5 a^2 b B+5 a^3 C+a b^2 (5 A+3 C)-3 b^3 B\right ) \left (-4 a^2 \sqrt{-\tan ^2(c+d x)} \sqrt{\sec (c+d x)} \Pi \left (-\frac{a}{b};\left .-\sin ^{-1}\left (\sqrt{\sec (c+d x)}\right )\right |-1\right )+2 b^2 \sqrt{-\tan ^2(c+d x)} \sqrt{\sec (c+d x)} \Pi \left (-\frac{a}{b};\left .-\sin ^{-1}\left (\sqrt{\sec (c+d x)}\right )\right |-1\right )-4 a b \sec ^2(c+d x)-2 b (2 a-b) \sqrt{-\tan ^2(c+d x)} \sqrt{\sec (c+d x)} F\left (\left .\sin ^{-1}\left (\sqrt{\sec (c+d x)}\right )\right |-1\right )+4 a b \sqrt{-\tan ^2(c+d x)} \sqrt{\sec (c+d x)} E\left (\left .\sin ^{-1}\left (\sqrt{\sec (c+d x)}\right )\right |-1\right )+4 a b\right )\right )}{a (a+b \cos (c+d x))}}{420 b^5 d \sqrt{\sec (c+d x)}} \]
Antiderivative was successfully verified.
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Maple [B] time = 4.052, size = 1097, normalized size = 3.2 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{C \cos \left (d x + c\right )^{2} + B \cos \left (d x + c\right ) + A}{{\left (b \cos \left (d x + c\right ) + a\right )} \sec \left (d x + c\right )^{\frac{5}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{C \cos \left (d x + c\right )^{2} + B \cos \left (d x + c\right ) + A}{{\left (b \cos \left (d x + c\right ) + a\right )} \sec \left (d x + c\right )^{\frac{5}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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